c# - Windows Forms OpenFileDialog, prevent opening instance if dialog already showing -

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i have openfiledialog instance on class, this.

public myclass {     public openfiledialog dialog { get; set; }      public myclass()     {         dialog = new openfiledialog();     }      public void showdialog()     {          if (dialog.showdialog() == dialogresult.ok)         {             dostuff(dialog.filenames);         }     } }

the issue if spam click button open dialog 3 times, dialog pop open once. once close first dialog, show additional 2 times. there way can detect if dialog showing prevent popping open?

edit: using unity3d experience utilizing mono version of system.windows.forms. because of this, there isn't form "owning" dialog, unity game window. button pushed gui element inside game.

thanks

try: 

dialog.showdialog(this);

assuming here this form contains button. should display dialog modal form it's owner preventing activating or using controls on form until dialog dismissed.


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