java - How to skip a header after regex match and read next line using BufferReader -

i have stream continue print rows follows:

11:19:54     cpu     %user     %nice   %system   %iowait    %steal     %idle 11:19:55          0.00      0.00      1.00      0.00      0.00     99.00 average:             0.00      0.00      1.00      0.00      0.00     99.00  11:19:55     cpu     %user     %nice   %system   %iowait    %steal     %idle 11:19:56          0.00      0.00      1.00      0.00      0.00     99.00 average:             0.00      0.00      1.00      0.00      0.00     99.00 

....so on

java code is:

    public final static string regex_starts_with_time = "[0-9]{2}:[0-9]{2}:[0-9]{2}\\s+[a-z]{2}\\s";     public final static string regex =  regex_starts_with_time + "cpu\\s+%usr\\s";     string line;     try {         inputstream = process.getinputstream();                         bufferedreader br = new bufferedreader(new inputstreamreader(is));          while ((line = br.readline()) != null) {             line.matches(regex);          //here want read next line skipping header.         }                 br.close();     } catch (ioexception e) {         ......     } 

i want skip header , read next line.

you can use string#contains("cpu") check if line contains sub-string. if does, (then header,) call continue in loop.

side note : can achieved using indexof() well. don't see reason use regex here .