Anagram test for two strings in python -

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this question:

write function named test_for_anagrams receives 2 strings parameters, both of consist of alphabetic characters , returns true if 2 strings anagrams, false otherwise. 2 strings anagrams if 1 string can constructed rearranging characters in other string using characters in original string once. example, strings "orchestra" , "carthorse" anagrams because each 1 can constructed rearranging characters in other 1 using characters in 1 of them once. note capitalization not matter here i.e. lower case character can considered same upper case character.

my code:

def test_for_anagrams (str_1, str_2):     str_1 = str_1.lower()     str_2 = str_2.lower()     print(len(str_1), len(str_2))     count = 0     if (len(str_1) != len(str_2)):         return (false)     else:         in range(0, len(str_1)):             j in range(0, len(str_2)):                 if(str_1[i] == str_2[j]):                     count += 1         if (count == len(str_1)):             return (true)         else:             return (false)   #main program str_1 = input("enter string 1: ") str_2 = input("enter string 2: ") result = test_for_anagrams (str_1, str_2) print (result)

the problem here when enter strings orchestra , carthorse, gives me result false. same strings the eyes , they see. appreciated.

i'm new python, excuse me if i'm wrong

i believe can done in different approach: sort given strings , compare them. 

def anagram(a, b):   # string list   str1 = list(a.lower())   str2 = list(b.lower())    #sort list   str1.sort()   str2.sort()    #join list string   str1 = ''.join(str1)   str2 = ''.join(str2)    return str1 == str2  print(anagram('orchestra', 'carthorse'))

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