arrays - C++ Checking if a double is within .1 of another double (+/-) -

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i'm running bit of code need compare 2 2d arrays variance. i've tried using following line of code check , compare values, test fails every time = if(arr1[a][b] != arr2[a][b] || arr1[a][b] + .1 != arr2[a][b] || arr1[a][b] - .1 != arr2[a][b]) {.

i know failing because of || statement, because 1 of requirements met. i've got find way determine if double stored in specific location in array matches other array in parallel location.

here's full code:

int numberoffailedcompares = 0; for(int = 0; < 20; a++) {     int b = 0;     while(b < 20) {          if(arr1[a][b] != arr2[a][b] || arr1[a][b] + .1 != arr2[a][b] || arr1[a][b] - .1 != arr2[a][b]) {             numberoffailedcompares++;             cout << numberoffailedcompares << endl;         }          b++;     } }

is there statement in c++ allow me check if value within +/- .1 threshold? 

if(arrlocation1 (+/- .1) == arrlocation1) { ...  }

"variance" means "within x", , not "equal plus x or minus x". instead of comparing equality, compare less/greater variance. so, example, test variance of +/- .1:

if (b >= a-.1 && b <= a+.1)

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