php - Inserting Data mysqli not working -

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here html form section... cant understand mistake

<!doctype html> <html>  <head>   <title></title>   <link rel="stylesheet" type="text/css" href="loginstyle.css">   <link href="bootstrap/css/bootstrap.min.css" rel="stylesheet">   <meta charset="utf-8">   <meta name="viewport" content="width=device-width, initial-scale=1 user-scalable=no">   <link href='https://fonts.googleapis.com/css?family=jura:600' rel='stylesheet' type='text/css'>   <link rel="stylesheet" type="text/css" href="font awseome glyphicons/css/font-awesome.min.css">   <link href='https://fonts.googleapis.com/css?family=lora:700' rel='stylesheet' type='text/css'>   <link href='https://fonts.googleapis.com/css?family=lato' rel='stylesheet' type='text/css'>   <link rel="stylesheet" href="owl carousel/owl-carousel/owl.carousel.css">   <link rel="stylesheet" href="owl carousel/owl-carousel/owl.theme.css"> </head>  <body>     <div class="container">     <div class="row">       <div class="col-md-12" style="margin-top:8%">         <h2 class="text-center">be part of world</h2>       </div>     </div>     <div class="row">       <div class="col-md-6 col-md-offset-3">         <form role="form" id="loginform" action="regcheck.php" method="post">           <div class="form-group">             <label for="regname">               <h4>name</h4>             </label>             <input type="text" id="regname" class="form-control" placeholder="your name here..." name="name">             <div class="alert"></div>           </div>           <div class="form-group">             <label for="reglogin">               <h4>login</h4>             </label>             <input type="text" placeholder="login here..." id="reglogin" class="form-control" name="login">             <div class="alert"></div>           </div>           <div class="form-group">             <label for="regpass">               <h4>password</h4>             </label>             <input type="password" placeholder="password here..." id="regpass" class="form-control" name="pass">             <div class="alert"></div>           </div>           <div class="form-group">             <input type="submit" value="sign up" class="btn btn-danger btn-lg" id="regsubmit" name="submit">           </div>         </form>       </div>     </div>     <div class="row">       <div class="col-md-12">         <h3 class="text-center"><strong>...0r join with</strong></h3>       </div>     </div>     <div class="row">       <div class="col-md-6 col-md-offset-4">         <ul class="list-inline">           <li><a href="facebook.com"><span class="fa fa-facebook-official " aria-hidden="true"></span> facebook</a>           </li>           <li><a href="twitter.com"><span class="fa fa-twitter" aria-hidden="true"></span> twitter</a>           </li>           <li><a href="youtube.com"><span class="fa fa-youtube " aria-hidden="true"></span> youtube</a>           </li>           <li><a href="instagram.com"><span class="fa fa-instagram " aria-hidden="true"></span> instagram</a>           </li>         </ul>       </div>     </div>   </div>    <script type="text/javascript" src="jquery/jquery-1.11.3.min.js"></script>   <script src="owl carousel/owl-carousel/owl.carousel.js"></script>   <script src="bootstrap/js/bootstrap.min.js"></script>   <script type="text/javascript" src="script.js"></script> </body>  </html>

here section checking registration

<?php $con = mysqli_connect("localhost", "root", ""); if (!$con) {     die("failed databse connection"); }  $name = $_post["name"]; $login = $_post["login"]; $pass = $_post["pass"]; $query = "insert db_users(name, pass,login) values ('$name', '$pass', '$login')";  if (isset($_post["submit"])) {     mysqli_query($con, $query); } ?>

this structure should be:

<?php      $con = mysqli_connect("host","username","password","database name");     if (!$con) {         die("failed databse connection");     }      $name = $_post["name"];     $login = $_post["login"];     $pass =  $_post["pass"];     $query = "insert db_users(name, pass,login) values ('$name', '$pass', '$login')";          if (isset($_post["submit"])) {             mysqli_query($con,$query);         }  ?>

but error non posted keys in post array try this:

<?php      $con = mysqli_connect("host","username","password","database name");     if (!$con) {         die("failed databse connection");     }           if (isset($_post["submit"])) {         $name = $_post["name"];         $login = $_post["login"];         $pass =  $_post["pass"];         $query = "insert db_users(name, pass,login) values ('$name', '$pass', '$login')";         mysqli_query($con,$query);         }  ?>

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